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Home » Could You Believe Where DC Really Is? The Shocking Location Will Surprise You! - ToelettAPP

Could You Believe Where DC Really Is? The Shocking Location Will Surprise You! - ToelettAPP

📅 March 9, 2026 👤 scraface

Mar 09, 2026

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📌 Now let \(r = \sqrt{x^2 + y^2}\), so:

📌 r^2 + z^2 = c r \quad \Rightarrow \quad r^2 - c r + z^2 = 0

📌 r^2 - c r + rac{c^2}{4} + z^2 = rac{c^2}{4} \quad \Rightarrow \quad \left(r - rac{c}{2}

📌 ight)^2 + z^2 = \left(rac{c}{2}

📌 This is the equation of a **circle** in the \( (r,z) \)-plane, rotated about the \(z\)-axis, forming a **torus**? No â actually, since \(r\) is radial, this describes a **sphere** of radius \(c/2\) centered at \((x, y, z) = (0, 0, 0, c/2)\) in cylindrical coordinates.

📌 Wait: \(\left(r - rac{c}{2}

📌 ight)^2\) is a circle in the \(r\)-axis plane, centered at \(r = c/2, z = 0\), radius \(c/2\). Rotated about the \(z\)-axis, this forms a **torus**? No â it forms a **sphere**.

📌 Indeed, expand:

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The original area of the triangle is:
A_{\text{original}} = \frac{1}{2} \times 8 \times 15 = 60 \text{ cm}^2
After increasing each leg by 2 cm, the new legs are 10 cm and 17 cm. T...
A_{\text{new}} = \frac{1}{2} \times 10 \times 17 = 85 \text{ cm}^2
- 60 = 25 \text{ cm}^2
Thus, the area increases by:
\boxed{25}
Question:** Find \(\sin 315^\circ\).
Since \(315^\circ = 360^\circ - 45^\circ\), we use the reference angle...
\sin 315^\circ = -\sin 45^\circ = -\frac{\sqrt{2}}{2}

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