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\fracab + c + \fracba + c + \fracca + b - ToelettAPP

📅 March 9, 2026 👤 scraface

Mar 09, 2026

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Plugging in the known values:
100^2 = 5200 + 2xy
= 5200 + 2xy
2xy = 4800 \quad \Rightarrow \quad xy = 2400
Now, we use another identity for cubes:
We already know \( x + y = 100 \), \( x^2 + y^2 = 5200 \), and \( xy =...
x^2 - xy + y^2 = 5200 - 2400 = 2800
x^3 + y^3 = 100 \times 2800 = 280000
\boxed{280000}
### Question:

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