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Home » Given \( A = 36\sqrt3 \), we solve for \( s \): - ToelettAPP

Given \( A = 36\sqrt3 \), we solve for \( s \): - ToelettAPP

📅 March 9, 2026 👤 scraface

Mar 09, 2026

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📌 \frac{\sqrt{3}}{4} s^2 = 36\sqrt{3}

📌 s^2 = 144 \quad \Rightarrow \quad s = 12

📌 If each side is decreased by 2 cm, the new side length is \( 10 \) cm. The new area \( A' \) is:

📌 A' = \frac{\sqrt{3}}{4} \times 10

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Substitute \( a = 1 \) and \( b = 2 \) into Equation 1:
+ 2 + c = 6 \\
+ c = 6 \\
c = 3
Thus, the values are \( a = 1 \), \( b = 2 \), and \( c = 3 \).
\boxed{(1, 2, 3)}
Question:** An angel investor is evaluating a startup's growth model,...
Solution:** We know the cubic polynomial \( f(t) = t^3 + pt^2 + qt + r...
\( f(0) = 2 \) implies \( r = 2 \).
\( f(1) = 0 \) implies \( 1 + p + q + r = 0 \).

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