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Home » Saleemarrm1 Sale Shock: Millions Have Been Burning Cash — Here’s How! - ToelettAPP

Saleemarrm1 Sale Shock: Millions Have Been Burning Cash — Here’s How! - ToelettAPP

📅 March 10, 2026 👤 scraface

Mar 10, 2026

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🔥 Popular Posts

Thus, the vector is $ \boxed{\left\langle \dfrac{4}{7}, \dfrac{1}{7},...
Question: Among all roots of the polynomial $ z^6 - z^4 + z^2 - 1 = 0...
Solution: Consider the polynomial:
z^6 - z^4 + z^2 - 1 = 0
So the roots satisfy either $ z^2 - 1 = 0 $ or $ z^4 + 1 = 0 $.
Roots from $ z^2 - 1 = 0 $:
$ z = \pm 1 $, both real, so imaginary part is 0.
Roots from $ z^4 = -1 $:
Write $ -1 = e^{i\pi} $, so:
z = e^{i(\pi + 2k\pi)/4} = e^{i\pi(2k+1)/4}, \quad k = 0, 1, 2, 3

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