Solution: The volume of the cylinder is $ V_{\textcyl} = \pi r^2 (6r) = 6\pi r^3 $. The volume of the cone is $ V_{\textcone} = \frac13 \pi (2r)^2 (3r) = \frac13 \pi (4r^2)(3r) = 4\pi r^3 $. The ratio is:

Solution: The volume of the cylinder is $ V_{\textcyl} = \pi r^2 (6r) = 6\pi r^3 $. The volume of the cone is $ V_{\textcone} = \frac13 \pi (2r)^2 (3r) = \frac13 \pi (4r^2)(3r) = 4\pi r^3 $. The ratio is: - ToelettAPP

📅 March 10, 2026 👤 scraface

Mar 10, 2026

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