The area \( A \) of an equilateral triangle with side length \( s \) is given by \( A = \frac{\sqrt3}4 s^2 \). The radius \( r \) of the inscribed circle in an equilateral triangle is \( r = \frac{s\sqrt3}6 \). The area of the circle is \( \pi r^2 = \pi \left(\frac{s\sqrt3}6\right)^2 = \frac\pi s^2 \cdot 336 = \frac\pi s^212 \). The ratio of the area of the triangle to the area of the inscribed circle is: - ToelettAPP