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Home » This Lotus Position Secret Will Transform Your Yoga Game Overnight! - ToelettAPP

This Lotus Position Secret Will Transform Your Yoga Game Overnight! - ToelettAPP

📅 March 10, 2026 👤 scraface

Mar 10, 2026

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But no option gives -1.
Wait — perhaps we misread:
Set \( \frac{dC}{dt} = -1 \):
-\frac{10}{(t+2)^2} = -1 \Rightarrow (t+2)^2 = 10 \Rightarrow t = \sqr...
Still not in choices. But perhaps question expects exact form?
But options are integers. So likely miscalculation.
Wait — if \( C(t) = 10/(t+2) \), then \( C'(t) = -10/(t+2)^2 \)
Set equal to -1:
-10/(t+2)^2 = -1 \Rightarrow (t+2)^2 = 10 \Rightarrow t = \sqrt{10} -...
But none of the integers satisfy.

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and $ L $ is a multiple of 7 (since pipes are seven units long and tot...
L \equiv 1 \pmod{13} \quad ext{and} \quad L \equiv 0 \pmod{7}
L \equiv 0 \pmod{7} \
Use the Chinese Remainder Theorem. Let $ L = 7k $. Substitute into the...
7k \equiv 1 \pmod{13}
We solve for $ k $: find the modular inverse of 7 modulo 13.
$ 7 \cdot 1 = 7
$ 7 \cdot 2 = 14 \equiv 1 \pmod{13} $
So $ 7^{-1} \equiv 2 \pmod{13} $
k \equiv 2 \pmod{13} \Rightarrow k = 13m + 2

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