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Home » Thus, the total number of arrangements is \(\boxed241920\). - ToelettAPP

Thus, the total number of arrangements is \(\boxed241920\). - ToelettAPP

📅 March 10, 2026 👤 scraface

Mar 10, 2026

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🔥 Popular Posts

> 32768, < 65536 → so 16 splits to reach ≤1? But we want exactly 1.
However, 64000 is not a power of 2, so we cannot reach exactly 1 via r...
But in practice, we split until each group is 1 — so must go until siz...
Start: 64000
After 1 split: 32000
After n splits: 64000 / 2ⁿ = 1 → 2ⁿ = 64000 → n = log₂(64000) = log₂(6...
But in discrete halving, we stop when size ≤1. But the question says "...
However, if the dataset is split recursively into two equal halves eac...
Re-evaluate: perhaps the split is theoretical — mathematically, how ma...
But the problem likely assumes idealized division — so answer is log₂(...

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4k \equiv 1 \pmod{7}
Multiplying both sides by the modular inverse of 4 modulo 7, which is...
k \equiv 2 \pmod{7}
So $k = 7m + 2$. Then $x = 60k = 60(7m + 2) = 420m + 120$. We seek the...
x = 420m + 120 \geq 100 \Rightarrow m \geq 0
Try $m = 0$: $x = 120$ (valid, three-digit). Check $120 \mod 7 = 1$?
\div 7 = 17 \text{ remainder } 1 \Rightarrow \text{Yes}
Thus, the smallest such number is $\boxed{120}$.
Question: What is the largest integer that must divide the product of...
Solution: Let the four consecutive odd integers be $n, n+2, n+4, n+6$,...

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