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Home » You Won’t Believe What the Second Hokage Did After Becoming Vill副! - ToelettAPP

You Won’t Believe What the Second Hokage Did After Becoming Vill副! - ToelettAPP

📅 March 10, 2026 👤 scraface

Mar 10, 2026

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📌 $a + d = 5$

📌 But $a + d = 7$ from (1) and $a + d = 5$ from (2) is a contradiction. Recheck: The second term is $a + d = 5$, and first + third is $a + (a + 2d) = 2a + 2d = 14$ → $a + d = 7$.

📌 But $a + d = 5$ and $a + d = 7$ is impossible. Therefore, no such sequence exists unless the problem is misinterpreted.

📌 Wait: The second term is $a + d = 5$, and $a + (a + 2d) = 14$ → $2a + 2d = 14$ → $a + d = 7$.

📌 Contradiction: $a + d = 5$ and $a + d = 7$ cannot both hold. Thus, no solution.

📌 But perhaps the problem meant the first term is $a$, third term is $a + 2d$, and their sum is 14, and second term is $a + d = 5$. Then:

📌 From $a + d = 5$, $a = 5 - d$. Substitute into $a + (a + 2d) = 14$:

📌 $(5 - d) + (5 - d + 2d) = 14$ → $5 - d + 5 + d = 10 = 14$ → $10 = 14$, impossible.

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Second term: \( a_2 = 2 \times 3 + 1 = 7 \)
Third term: \( a_3 = 2 \times 7 + 1 = 15 \)
Fourth term: \( a_4 = 2 \times 15 + 1 = 31 \)
Fifth term: \( a_5 = 2 \times 31 + 1 = 63 \)
A rectangular garden has a length that is 4 meters more than twice its...
Let width = \( w \) meters, then length = \( 2w + 4 \) meters
Perimeter equation: \( 2(w + (2w + 4)) = 68 \)
Simplifying: \( 2(3w + 4) = 68 \)
\( 6w + 8 = 68 \)
\( 6w = 60 \)

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